MCQ 11 Mark
Assertion (A) : $\frac{\sin 27^9}{\cos 63^2}=1$
Reason (R) : $\sin (90-\theta)=\cos \theta$ and $\cos (90-\theta)=\sin \theta$.
View full question & answer→MCQ 21 Mark
Assertion (A) : In a right angled $\triangle ABC$, if $\angle ABC =90, AB =3 cm, BC =4 cm$, then $\sin A=\cos C$.
Reason (R) : $\frac{\sin \theta}{\cos \theta}=\tan \theta$ and $\sin \theta \quad \cos \theta=\cot \theta$.
View full question & answer→MCQ 31 Mark
Assertion (A) : The value of $\sin 60 \cos 30+\cos 60 \sin 30$ is 0 .
Reason (R) : $\sin 90=0$ and $\sin 0=1$.
View full question & answer→MCQ 41 Mark
The value of $\left(\cos 0^{\circ}+\sin 45^{\circ}+\sin 30^{\circ}\right)\left(\sin 90^{\circ}-\cos 45^{\circ}+\cos 60^{\circ}\right)=$
- A
$\frac{3}{5}$
- B
$\frac{5}{6}$
- ✓
$\frac{7}{4}$
- D
$\frac{5}{8}$
AnswerCorrect option: C. $\frac{7}{4}$
View full question & answer→MCQ 51 Mark
The value of $\tan 5 \tan 25 \tan 30^{\circ} \tan 65 \tan 85=$
- A
- B
$\sqrt{3}$
- ✓
$\frac{1}{\sqrt{3}}$
- D
AnswerCorrect option: C. $\frac{1}{\sqrt{3}}$
View full question & answer→MCQ 61 Mark
If $3 \sin \theta+4 \cos \theta=5$, then the value of $\sin \theta$ is :
- A
$\frac{3}{4}$
- ✓
$\frac{3}{5}$
- C
$\frac{4}{5}$
- D
$\frac{5}{3}$
AnswerCorrect option: B. $\frac{3}{5}$
View full question & answer→MCQ 71 Mark
The value of $\frac{\tan 35}{\cot 55}+\frac{\cot 78}{\tan 12}=$
View full question & answer→MCQ 81 Mark
The value of $\sin ^2 25+\sin ^2 65=$
View full question & answer→MCQ 91 Mark
The value of $\sin \theta \cos \left(90^{\circ}-\theta\right)+\cos \theta \sin \left(90^{\circ}-\theta\right)=$
View full question & answer→MCQ 101 Mark
In $\triangle ABC , \angle B =90^{\circ}, AB =5 cm$ and $BC =12 cm$. Then $\sin C =$
- A
$\frac{12}{13}$
- ✓
$\frac{5}{13}$
- C
$\frac{5}{12}$
- D
$\frac{13}{5}$
AnswerCorrect option: B. $\frac{5}{13}$
View full question & answer→MCQ 111 Mark
If $5 \cot \theta=3$, then $\frac{\left(5 \sin \theta-\frac{1}{2}\right.}{(4 \sin \theta+3 \cos \theta)}=$
- A
$\frac{11}{18}$
- ✓
$\frac{16}{29}$
- C
$\frac{14}{27}$
- D
$\frac{29}{16}$
AnswerCorrect option: B. $\frac{16}{29}$
View full question & answer→MCQ 121 Mark
If $\sin \theta=\frac{1}{2}$, then \left(3 \cos \theta^{17} 4 \cos ^3 \theta\right)=
- ✓
- B
$\frac{1}{2}$
- C
$\frac{1}{6}$
- D
View full question & answer→MCQ 131 Mark
If $\sin \theta=\frac{8}{17}$, then $\cot \theta=$
- ✓
$\frac{15}{8}$
- B
$\frac{15}{17}$
- C
$\frac{8}{15}$
- D
$\frac{17}{8}$
AnswerCorrect option: A. $\frac{15}{8}$
View full question & answer→MCQ 141 Mark
If $\theta$ is an acute angle and $\sin (\theta+18)=\frac{1}{2}$, then $\operatorname{cosec} 5 \theta=$
- A
- B
$\sqrt{2}$
- C
- ✓
$\frac{2}{\sqrt{3}}$
AnswerCorrect option: D. $\frac{2}{\sqrt{3}}$
View full question & answer→MCQ 151 Mark
If $\cos 2 \theta=0$ and $\theta$ is an acute angle, then $\cot \left(\begin{array}{ll}\theta & 15\end{array}\right)=$
- A
$\frac{1}{\sqrt{3}}$
- B
- ✓
$\sqrt{3}$
- D
AnswerCorrect option: C. $\sqrt{3}$
View full question & answer→MCQ 161 Mark
If $\sin \theta=\cos \theta$, then $\sec (\theta+15)=$
- A
$\sqrt{2}$
- ✓
- C
$\frac{2}{\sqrt{3}}$
- D
View full question & answer→MCQ 171 Mark
If $0 \leq \theta \leq 90$ and $\tan (\theta+15)=1$, then $\cos 2 \theta=$
- ✓
$\frac{1}{2}$
- B
$\frac{\sqrt{3}}{2}$
- C
$\frac{1}{\sqrt{2}}$
- D
AnswerCorrect option: A. $\frac{1}{2}$
View full question & answer→MCQ 181 Mark
If $x \tan 30=\cos 60$, then $x=$
- A
- B
$\frac{2}{\sqrt{3}}$
- ✓
$\frac{\sqrt{3}}{2}$
- D
$\frac{1}{2}$
AnswerCorrect option: C. $\frac{\sqrt{3}}{2}$
View full question & answer→MCQ 191 Mark
If $0 \leq \theta \leq 90$ and $\cos (\theta \quad 30)=\frac{1}{2}$, then $\tan \theta=$
- A
$\sqrt{3}$
- B
- C
$\frac{1}{\sqrt{2}}$
- ✓
View full question & answer→MCQ 201 Mark
If $\theta$ is an acute angle and $\sin (\theta \quad 15)=\frac{1}{2}$, then $\cos (\theta-15)=$
- A
$\frac{1}{2}$
- ✓
$\frac{\sqrt{3}}{2}$
- C
$\frac{1}{\sqrt{2}}$
- D
AnswerCorrect option: B. $\frac{\sqrt{3}}{2}$
View full question & answer→MCQ 211 Mark
The value of $\left(\cos 0^{\circ}+\sin 45^{\circ}+\sin 30^{\circ}\right)\left(\sin 90^{\circ}-\cos 45^{\circ}+\cos 60^{\circ}\right)=$
- A
$\frac{3}{5}$
- B
$\frac{5}{6}$
- ✓
$\frac{7}{4}$
- D
$\frac{5}{8}$
AnswerCorrect option: C. $\frac{7}{4}$
View full question & answer→MCQ 221 Mark
The value of $\tan 5^{\circ} \tan 25^{\circ} \tan 30^{\circ} \tan 65^{\circ} \tan 85^{\circ}=$
- A
- B
$\sqrt{3}$
- ✓
$\frac{1}{\sqrt{3}}$
- D
AnswerCorrect option: C. $\frac{1}{\sqrt{3}}$
View full question & answer→MCQ 231 Mark
If $3 \sin \theta+4 \cos \theta=5$, then the value of $\sin \theta$ is :
- A
$\frac{3}{4}$
- ✓
$\frac{3}{5}$
- C
$\frac{4}{5}$
- D
$\frac{5}{3}$
AnswerCorrect option: B. $\frac{3}{5}$
View full question & answer→MCQ 241 Mark
The value of $\frac{\tan 35^{\circ}}{\cot 55^{\circ}}+\frac{\cot 78^{\circ}}{\tan 12^{\circ}}=$
View full question & answer→MCQ 251 Mark
The value of $\sin ^2 25^{\circ}+\sin ^2 65^{\circ}=$
View full question & answer→MCQ 261 Mark
The value of $\sin \theta \cos \left(90^{\circ}-\theta\right)+\cos \theta \sin \left(90^{\circ}-\theta\right)=$
View full question & answer→MCQ 271 Mark
In $\triangle ABC , \angle B =90^{\circ}, AB =5 cm$ and $BC =12 cm$. Then $\sin C =$- A
$\frac{12}{13}$
- ✓
$\frac{5}{13}$
- C
$\frac{5}{12}$
- D
$\frac{13}{5}$
AnswerCorrect option: B. $\frac{5}{13}$
View full question & answer→MCQ 281 Mark
If $5 \cot \theta=3$, then $\frac{(5 \sin \theta-3 \cos \theta)}{(4 \sin \theta+3 \cos \theta)}=$
- A
$\frac{11}{18}$
- ✓
$\frac{16}{29}$
- C
$\frac{14}{27}$
- D
$\frac{29}{16}$
AnswerCorrect option: B. $\frac{16}{29}$
View full question & answer→MCQ 291 Mark
If sin $\theta=\frac{1}{2}$, then $(3 \cos \theta$ - $\left.4 \cos ^3 \theta\right)=$
- ✓
$0$
- B
$\frac{1}{2}$
- C
$\frac{1}{6}$
- D
View full question & answer→MCQ 301 Mark
If sin $\theta=\frac{8}{17}$, then $\cot \theta=$
- ✓
$\frac{15}{8}$
- B
$\frac{15}{17}$
- C
$\frac{8}{15}$
- D
$\frac{17}{8}$
AnswerCorrect option: A. $\frac{15}{8}$
View full question & answer→MCQ 311 Mark
If $\theta$ is an acute angle and $\sin \left(\theta+18^{\circ}\right)=\frac{1}{2}$, then $\operatorname{cosec} 5 \theta=$
- A
- B
$\sqrt{2}$
- C
- ✓
$\frac{2}{\sqrt{3}}$
AnswerCorrect option: D. $\frac{2}{\sqrt{3}}$
View full question & answer→MCQ 321 Mark
If $\cos 2 \theta=0$ and $\theta$ is an acute angle, then $\cot \left(\theta-15^{\circ}\right)=$
- A
$\frac{1}{\sqrt{3}}$
- B
- ✓
$\sqrt{3}$
- D
AnswerCorrect option: C. $\sqrt{3}$
View full question & answer→MCQ 331 Mark
If $\sin \theta=\cos \theta$, then $\sec \left(\theta+15^{\circ}\right)=$
- A
$\sqrt{2}$
- ✓
- C
$\frac{2}{\sqrt{3}}$
- D
View full question & answer→MCQ 341 Mark
If $0^{\circ} \leq \theta \leq 90^{\circ}$ and $\tan \left(\theta+15^{\circ}\right)=1$, then $\cos 2 \theta=$
- ✓
$\frac{1}{2}$
- B
$\frac{\sqrt{3}}{2}$
- C
$\frac{1}{\sqrt{2}}$
- D
$0$
AnswerCorrect option: A. $\frac{1}{2}$
View full question & answer→MCQ 351 Mark
If $x \tan 30^{\circ}=\cos 60^{\circ}$, then $x=$
- A
- B
$\frac{2}{\sqrt{3}}$
- ✓
$\frac{\sqrt{3}}{2}$
- D
$\frac{1}{2}$
AnswerCorrect option: C. $\frac{\sqrt{3}}{2}$
View full question & answer→MCQ 361 Mark
If $0^{\circ} \leq \theta \leq 90^{\circ}$ and $\cos \left(\theta-30^{\circ}\right)=\frac{1}{2}$, then $\tan \theta=$
- A
$\sqrt{3}$
- B
- C
$\frac{1}{\sqrt{2}}$
- ✓
View full question & answer→MCQ 371 Mark
If $\theta$ is an acute angle and $\sin \left(\theta-15^{\circ}\right)=\frac{1}{2}$, then $\cos \left(\theta-15^{\circ}\right)=$
- A
$\frac{1}{2}$
- ✓
$\frac{\sqrt{3}}{2}$
- C
$\frac{1}{\sqrt{2}}$
- D
AnswerCorrect option: B. $\frac{\sqrt{3}}{2}$
View full question & answer→MCQ 381 Mark
Assertion (A) : $\frac{\sin 27^{\circ}}{\cos 63^{\circ}}=1$.
Reason (R) : $\sin \left(90^{\circ}-\theta\right)=\cos \theta$ and $\cos \left(90^{\circ}-\theta\right)=\sin \theta$.
View full question & answer→MCQ 391 Mark
Assertion (A) : In a right angled $\triangle A B C$, if $\angle A B C=90^{\circ}, A B=3 cm, B C=4 cm$, then $\sin A=\cos C$.
Reason (R) : $\frac{\sin \theta}{\cos \theta}=\tan \theta$ and $\sin \theta \times \cos \theta=\cot \theta$.
View full question & answer→MCQ 401 Mark
Assertion (A) : The value of $\sin 60^{\circ} \cos 30^{\circ}+\cos 60^{\circ} \sin 30^{\circ}$ is 0.
Reason (R) : $\sin 90^{\circ}=0$ and $\sin 0^{\circ}=1$.
View full question & answer→