Question
In $\triangle ABC,$ angle $B$ is obtuse. $D$ and $E$ are mid$-$points of sides $\text{AB}$ and $\text{BC}$ respectively and $F$ is a point on side $\text{AC}$ such that $\text{EF}$ is parallel to $\text{AB}.$ Show that $\text{BEFD}$ is a parallelogram.

Answer

The figure is shown below

From figure $\text{EF} \| \text{AB}$ and $E$ is the mid$-$point of $\text{BC}$.
Therefore $F$ is the midpoint of $\text{AC}$.
Here $\text{EF} \| \text{BD} , \text{EF} = \text{BD}$ as $D$ is the midpoint of $\text{AB}$
$\text{BE} \| \text{DF} , \text{BE} = \text{DF}$ as $E$ is the midpoint of $\text{BC}$.
Therefore $\text{BEFD}$ is a parallelogram.

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