In ABC , B ( A + B ) = - Vidyadip

MCQ

In $\triangle ABC , \frac{\sin B }{\sin ( A + B )}=$

A
$\frac{b}{a+b}$
✓
$\frac{ b }{ c }$
C
$\frac{c}{b}$
D
$\frac{b}{a+c}$

✓

Answer

Correct option: B.

$\frac{ b }{ c }$

(B) $\frac{\sin B}{\sin (A+B)}=\frac{\sin B}{\sin C}=\frac{b}{c}$ $\ldots .[\because A+B+C=\pi, A+B=\pi-C]$

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