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Trigonometric Functions — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsTrigonometric Functions2 Marks
MCQ
In $\triangle ABC$ if $c^2+a^2-b^2=a c$, then $\angle B=......$
  • A
    $\frac{\pi}{4}$
  • ✓
    $\frac{\pi}{3}$
  • C
    $\frac{\pi}{2}$
  • D
    $\frac{\pi}{6}$
✓

Answer

Correct option: B.
$\frac{\pi}{3}$
$c^2+a^2-b^2=a c$
$\therefore \frac{c^2+a^2-b^2}{2 a c}=\frac{1}{2}$
$\therefore \cos B=\frac{1}{2}, $
$\therefore \angle B=\frac{\pi}{3}$
Hence option $(b)$

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