Question
In $\triangle ABC$, prove that $\tan \left(\frac{ C - A }{2}\right)=\left(\frac{c-a}{c+a}\right) \cot \frac{ B }{2}$
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$\tan ^{-1}\left(\frac{x}{1+6 x^2}\right)+\cot ^{-1}\left(\frac{1-10 x^2}{7 x}\right)$