In , if =90^ , then BC2 = (___) + (___). - Vidyadip

Question

In $\triangle\text{ABC},$ if $\angle\text{A}=90^\circ,$ then BC² = (___) + (___).

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Answer

In $\triangle\text{ABC},$ if $\angle\text{A}=90^\circ,$ then: $\text{BC}^2=(\underline{\text{AB}})^2+(\underline{\text{AC}})^2$

Solution:

In $\triangle\text{ABC},$ if $\angle\text{A}=90^\circ,$ then by pythagoras theoram:

$\text{BC}^2=\text{AB}^2+\text{AC}^2$

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