Question 11 Mark
The sum of the angles of a triangle is _____.
Answer
View full question & answer→The sum of the angles of a triangle is 180°.
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Question 21 Mark
The sum of any two sides of a triangle is always _____ than the third side.
Answer
View full question & answer→The sum of any two sides of a triangle is always greater than the third side.
Question 31 Mark
In the given figure, side BC of $\triangle\text{ABC}$ is produced to D and $\text{CE}||\text{BA.}$ If $\angle\text{BAC}=50^\circ$ then $\angle\text{ACE}=\text{_____.}$
Answer
View full question & answer→In the given figure, side BC of $\triangle\text{ABC}$ is produced to D and $\text{CE}||\text{BA.}$ If $\angle\text{BAC}=50^\circ$, then $\angle\text{ACE}=\underline{\text{50}}^\circ$
Solution:
$\text{AB}||\text{CE}$ $\therefore\angle\text{BAC}=\angle\text{ACE}=50^\circ$ (alternate angles)Question 41 Mark
In $\triangle\text{ABC},$ if $\angle\text{A}=90^\circ,$ then BC2 = (___) + (___).
Answer
View full question & answer→In $\triangle\text{ABC},$ if $\angle\text{A}=90^\circ,$ then: $\text{BC}^2=(\underline{\text{AB}})^2+(\underline{\text{AC}})^2$
Solution:
In $\triangle\text{ABC},$ if $\angle\text{A}=90^\circ,$ then by pythagoras theoram: $\text{BC}^2=\text{AB}^2+\text{AC}^2$Question 51 Mark
In $\triangle\text{ABC},$ AB = AC and $\text{AD}\bot\text{BC},$ then BD = _____.
Answer
View full question & answer→In $\triangle\text{ABC}:\text{AB}=\text{AC},\text{AD}\bot\text{BC}$ Then, $\text{BD}=\underline{\text{DC}}$
Solution:
$\text{BD}=\text{DC}$
This is because in an isosceles triangle, the perpendicular dropped from the vertex joining the equal sides, bisects the base.