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Triangles — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsTriangles1 Mark
MCQ
In $\triangle\text{ABC}$ and $\triangle\text{PQR},$ we have $\frac{\text{AB}}{\text{QR}}=\frac{\text{BC}}{\text{PR}}=\frac{\text{CA}}{\text{PQ}}$ then:
  • ✓
    $\triangle\text{PQR}\sim\triangle\text{CAB}$
  • B
    $\triangle\text{PQR}\sim\triangle\text{ABC}$
  • C
    $\triangle\text{CAB}\sim\triangle\text{PQR}$
  • D
    $\triangle\text{BCA}\sim\triangle\text{PQR}$
✓

Answer

Correct option: A.
$\triangle\text{PQR}\sim\triangle\text{CAB}$
In $\triangle\text{ABC}$ and $\triangle\text{DEF},$
$\frac{\text{AB}}{\text{QR}}=\frac{\text{BC}}{\text{PR}}=\frac{\text{CA}}{\text{PQ}}$
So, $\angle\text{A}\leftrightarrow\angle\text{Q},\angle\text{B}\leftrightarrow\angle\text{R},\angle\text{C}\leftrightarrow\angle\text{P},$
$\Rightarrow\triangle\text{CAB}\sim\triangle\text{PQR}$

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