Question
In $\triangle\text{ABC},$ if $\angle\text{B}=76^\circ$ and $\angle\text{C}=48^\circ,$ find $\angle\text{A}.$
✓
Answer
Since, sum of the angles of a triangle is $180^{\circ} \angle A +\angle B +\angle C =180^{\circ}$
$\Rightarrow \angle A+76^{\circ}+ 4 8 ^ { \circ } =180^{\circ}$
$\Rightarrow \angle A=180^{\circ}-124^{\circ}=56^{\circ}$
$\therefore \angle A=56^{\circ}$
$\Rightarrow \angle A+76^{\circ}+ 4 8 ^ { \circ } =180^{\circ}$
$\Rightarrow \angle A=180^{\circ}-124^{\circ}=56^{\circ}$
$\therefore \angle A=56^{\circ}$
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