Question
Subtract the second polynomial from the first :
$2 a b^2+3 a^2 b-4 a b ; 3 a b-8 a b^2+2 a^2 b$
$2 a b^2+3 a^2 b-4 a b ; 3 a b-8 a b^2+2 a^2 b$
✓
Answer
$\left(2 a b^2+3 a^2 b-4 a b\right)-\left(3 a b-8 a b^2+2 a^2 b\right)$
$=2 a b^2+3 a^2 b-4 a b-3 a b+8 a b^2-2 a^2 b$
$=2 a b^2+8 a b^2+3 a^2 b-2 a^2 b-4 a b-3 a b$
$=10 a b^2+a^2 b-7 a b$
$=2 a b^2+3 a^2 b-4 a b-3 a b+8 a b^2-2 a^2 b$
$=2 a b^2+8 a b^2+3 a^2 b-2 a^2 b-4 a b-3 a b$
$=10 a b^2+a^2 b-7 a b$
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