MCQ
In $\triangle\text{ABC},\angle\text{B}=\angle\text{C}$ and ray $AX$ bisects the exterior angle $\angle\text{DAC}.$ If $\angle\text{DAX}=70^\circ$ then $\angle\text{ACB}=$
- A$35^\circ$
- B$90^\circ$
- ✓$70^\circ$
- D$55^\circ$

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