MCQ
In which compound, the oxidation state of phosphorus is $+4$
- A${P_4}{O_{11}}$
- ✓${P_4}{O_8}$
- C$PC{l_5}$
- D$NC{l_5}$
$4 x+(-2 \times 8)=0$
$4 x-16=0$
$x=\frac{16}{4}=+4$
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${C_6}{H_5} - O - C{H_2} - C{H_3}\xrightarrow{{Excess\,HI/\Delta }}\left[ X \right] + \left[ Y \right]$
$[X]$ and $[Y]$ will respectively be