Question
In $YDSE$ experiment, when two light rays make third minima, then they have
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Answer
For minima, path difference $\Delta=(2 n-1) \frac{\lambda}{2}$
For third minima $n=3 \Rightarrow \Delta=(2 \times 3-1) \frac{\lambda}{2}=\frac{5 \lambda}{2}$
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