MCQ
In Young's double slit experiment, the intensity at a point where path difference is $\frac{\lambda}{6}$ is $l$. If $l_0$ denotes the maximum intensity, $\frac{l}{l_0}$.
  • A
    $\frac{1}{\sqrt{2}}$
  • B
    $\frac{\sqrt{3}}{2}$
  • C
    $\frac{1}{2}$
  • $\frac{3}{4}$

Answer

Correct option: D.
$\frac{3}{4}$
d
(d)

Where, $\Delta x=\frac{\lambda}{6}$

$\Delta \phi=\frac{2 \pi}{\lambda} \Delta x$

$\therefore \Delta \phi=\frac{\pi}{3}$

$I=I_0 \cos ^2\left(\frac{\Delta \phi}{2}\right)$

$I=I_0 \cos ^2\left(\frac{\pi}{6}\right)$

or $I=I_0 \times \frac{3}{4}$

$\therefore \quad \frac{I}{I_0}=\frac{3}{4}$

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