In Young's double slit experiment the two slits are 0.6 ; mm dist… - Vidyadip

MCQ

In Young's double slit experiment the two slits are $0.6 \; mm$ distance apart. Interference pattern is observed on a screen at a distance $80 \; cm$ from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light will be $\dots \; nm .$

✓
$450$
B
$550$
C
$650$
D
$750$

✓

Answer

Correct option: A.

$450$

a
$d=0.6 \times 10^{-3}$

$D=80 \times 10^{-2}$

$1st$ Dark fringe $=\frac{D \lambda}{2 d}=\frac{d}{2}, \quad \lambda=\frac{d^{2}}{D}$

$=450 \times 10^{-9} \; m$

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