Question
In Young's experiment, the separation between $5^{\text {th }}$ maxima and $3^{\text {rd }}$ minima is how many times as that of fringe width is ........ times
✓
Answer
(c)
$5^{\text {th }} \text { maximum }=\frac{5 \lambda D}{d}$
$3^{\text {nd }} \text { minimum }=\frac{(2 n-1) \lambda . D}{2 d}=\frac{5 \lambda D}{2 d}$
$\therefore \quad \text { Distance }=\frac{5 \lambda D}{d}-\frac{5 \lambda D}{2 d}$
$=\frac{5 \lambda D}{2 d}$
$\therefore \text { Distance }=2.5 \text { times }$
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