MCQ
ind the value of $\text{cot}\text{(tan}^1\text{a}+\text{cot}^1\text{a}).$
 
  • $0$
  • B
    $−1$
  • C
    $2$
  • D
    $1$

Answer

Correct option: A.
$0$
We know,
$\tan^1\text{a}+\cot^{-1}\text{a}=\frac{\pi}{2}$
Therefore,
$\cot(\tan^{−1}\text{a}+\cot^{−1}a)=\cot\frac{\pi}{2}=0$

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