(2) $\left[\mathrm{Co}(\mathrm{CN})_{5}(\mathrm{NC})\right]^{-3}$ can't Show $G.I.$
(3) $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{2}\right)_{3}\right]$
Show fac $\&$ mer isomerism
(4) $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]^{\oplus}$ show cis $\&$ trans isomerism
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$(1)$ Reaction of gold with aqua regia produces $NO _2$ in the absence of air
$(2)$ Aqua regia is prepared by mixing conc. $HCl$ and conc. $HNO _3$ in $3: 1$ ($v/v$) ratio
$(3)$ Reaction of gold with aqua regia produces an anion having $Au$ in +$3$ oxidation state
$(4)$ The yellow colour of aqua regia is due to the presence of $NOCl$ and $Cl _2$
Reason : Oxygen forms $p\pi \,-\, p\pi $ multiple bond due to small size and small bond length but $p\pi \,-\,p\pi $ bonding is not possible in sulphur.
$C{H_3}C{H_2}OH\xrightarrow{{P + {I_2}}}A\xrightarrow[{Ether}]{{Mg}}B $ $\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D,$
then compound $'D'$ is -
$(A)$ Hydrolysis of Marshall's acid gives $H_2SO_4$ and $H_2O_2$ as final product
$(B)$ In $SCNSiH_3$ structure around $N$ is bent
$(C)$ Basic unit for silicates is $SiO_4^{-4}$
$(D)$$N{H_4}Cl + NaOH \to N{H_3} \uparrow $