- A$Xe < Kr < Ne < He$
- B$He < Ne < Kr < Xe$
- ✓$He < Xe < Kr < Ne$
- D$He < Kr < Xe < Ne$
So, order is $Ne > Kr > Xe > He$
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$\underset{(A)}{\mathop{\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}}, \\
\end{matrix}}}\,\,\,\,\,\underset{(B)}{\mathop{\begin{matrix}
\,\,\,\,\,\,O \\
\,\,\,\,\,\,|| \\
C{{H}_{3}}-C-H, \\
\end{matrix}}}\,\,\,\,\,\underset{(C)}{\mathop{\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\, \,\, \\
C{{H}_{3}}-C-C{{H}_{2}}-Cl, \\
\end{matrix}}}\,$ $\,\,\underset{(D)}{\mathop{\begin{matrix}
O \\
|| \\
H-C-H, \\
\end{matrix}}}\,\,\,\,\underset{(E)}{\mathop{\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
Cl-C{{H}_{2}}-C-H \\
\end{matrix}}}\,$
$\left( {{C_2}O_4^{2 - } = } \right.$ Oxalato $)$
Statement $I$ : Picric acid is $2, 4, 6$-trinitrotoluene.
Statement $II$ : Phenol$-2, 4-$disulphuric acid is treated with conc. $\mathrm{HNO}_3$ to get picric acid.
In the light of the above statement, choose the most appropriate answer from the options given below :
Item$-I$ Item$-II$
$(I)$ Benzene $( P )$ $HCl$ and $SnCl _{2}, H _{3} O ^{+}$
$(II)$ Benzonitrile $(Q)$ $H _{2}, Pd - BaSO _{4}, S$ and quinoline
$(III)$ Benzoyl Chloride $(R)$ $CO , HCl$ and $AlCl _{3}$