- ANo vacant $d$ - orbital
- ✓High dissociation energy
- CHigh electronegativity
- DNone
So, inertness of $N _2$ is due to high dissociation energy of $N _2$.
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$2KHCO_3(s) \to K_2O(s) + 2CO_2(g) + H_2O(g)$
$2 NO _{( g )}+ O _{2}( g ) \rightleftarrows 2 NO _{2}( g )$
The reaction occurring as above comes to equilibrium under a total pressure of 1 atom. Analysis of the system shows that $0.6 mol$ of oxygen are present at equilibrium. The equilibrium constant for the reaction is $.........$(Nearest integer).
$A: \left[ Ni ( en )_{3}\right]^{2+}, B :\left[ Ni \left( NH _{3}\right)_{6}\right]^{2+}, C :\left[ Ni \left( H _{2} O \right)_{6}\right]^{2+}$
$Zn_{(s)} +Cu^{+2}_{(aq)} \to Zn^{2+}_{(aq)} +Cu_{(s)}$
$[E^o_{Cu^{+2 /Cu}} = 0.34\,V$ , $E^o_{Zn^{2+} /Zn} = -0.76\,V ]$
$A$. $\mathrm{Be} \rightarrow \mathrm{Be}^{-}$
$B$. $\mathrm{N} \rightarrow \mathrm{N}^{-}$
$C$. $\mathrm{O} \rightarrow \mathrm{O}^{2-}$
$D$. $\mathrm{Na} \rightarrow \mathrm{Na}^{-}$
$E$. $\mathrm{Al} \rightarrow \mathrm{Al}^{-}$
Choose the most appropriate answer from the options given below :
