MCQ
Inertness of ${N_2}$ gas is due to
- ANo vacant $d$ - orbital
- ✓High dissociation energy
- CHigh electronegativity
- DNone
So, inertness of $N _2$ is due to high dissociation energy of $N _2$.
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$PhCHO + Ph \cdot CHO \xrightarrow[in\,\,{{D}_{2}}O]{NaOD} A + \begin{matrix} O \\ || \\ Ph-C-{{O}^{-}} \\ \end{matrix}$$\left( Ph\right.$ is $\left.- C _{6} H _{5}\right)$
($R$ is gas constant)

[Note : Ignore the pairing energy]
