MCQ
Initially spring is in natural length and both blocks are in rest condition. Then determine Maximum extension is spring. $k=20 N / M$
- ✓$\frac{20}{3} \,cm$
- B$\frac{10}{3}\, cm$
- C$\frac{40}{3} \,cm$
- D$\frac{19}{3} \,cm$
✓
Answer
Correct option: A.
$\frac{20}{3} \,cm$
a
Using the work energy theorem,
Using the work energy theorem,
$\left(F-m_{1} a\right) x_{1}+\left(m_{2} a\right) x_{2}-\frac{1}{2} k\left(x_{1}+x_{2}\right)^{2}=0$
$m_{2}\left(\frac{F}{m_{1}+m_{2}}\right)\left(x_{1}+x_{2}\right)=\frac{k}{2}\left(x_{1}+x_{2}\right)^{2}$
$\left(x_{1}+x_{2}\right)=m_{2}\left(\frac{F}{m_{1}+m_{2}}\right)\left(\frac{2}{k}\right)$
$=\frac{1(1)}{1.5}\left(\frac{2}{20}\right)$
Further simplify the above,
$\frac{1}{15} m =\frac{100}{15} cm$
$=\frac{20}{3} cm$
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