MCQ
Inorganic graphite is
- A${B_3}{N_3}{H_6}$
- ✓${B_3}{N_3}$
- C$SiC$
- D$Fe{(CO)_5}$
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$\begin{matrix}
O\,\,\,\, \\
\,||\,\,\,\, \\
C{{H}_{3}}-C-Cl\xrightarrow{{{H}_{2}}S} \\
\end{matrix}$ product
Reason : Oxidation state of $Cr$ in $Na_2CrO_4$ is $+VI$

|
सूची-$I$ coordination compounds |
सूची-$II$ numbar of unpaired electrons |
| $A$ $\left[ Cr ( CN )_6\right]^{3-}$ | $I$ $0$ |
| $B$ $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$ | $II$ $3$ |
| $C$ $\left[ Co \left( NH _3\right)_6\right]^{3+}$ | $III$ $2$ |
| $D$ $\left[ Ni \left( NH _3\right)_6\right]^{2+}$ | $IV$ $4$ |
Choose the correct answer from the options given below :-