- A$\frac{0.1\text{V}}{\text{s}}$
- B$\frac{1\text{V}}{\text{s}}$
- C$\frac{10^6\text{V}}{\text{s}}$
- D$\frac{10^{-6}\text{V}}{\text{s}}$
Explanation:
In a capacitor of capacitance C,
$\text{V}=\frac{\text{q}}{\text{C}}$
$\Rightarrow\frac{\text{dV}}{\text{dt}}=\frac{\text{i}}{\text{C}}=\frac{1\text{A}}{1\mu\text{F}}=\frac{10^6\text{V}}{\text{s}}$
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