MCQ
$\int_{}^{} {\frac{{{{(1 + \log x)}^2}}}{x}} \;dx = $
  • A
    ${(1 + \log x)^3} + c$
  • B
    $3{(1 + \log x)^3} + c$
  • $\frac{1}{3}{(1 + \log x)^3} + c$
  • D
    None of these

Answer

Correct option: C.
$\frac{1}{3}{(1 + \log x)^3} + c$
c
(c)Put $(1 + \log x) = t \Rightarrow \frac{1}{x}dx = dt$
$\int_{}^{} {\frac{{{{(1 + \log x)}^2}}}{x}\,dx = \int_{}^{} {{t^2}dt} } $$ = \frac{{{t^2}}}{3} + c = \frac{{{{(1 + \log x)}^3}}}{3} + c.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $f$ be a function such that $f(x)\, = \,\sum\limits_{n\, - \,1}^n {\left[ {r\, + \,\cos \frac{x}{r}} \right]} $ where [.] denotes greatest integer function and $x \in [0,\pi]$, then range of   $f(x)$ is-
Choose the correct answer from the given four options.
The vectors from origin to the points A and B are $\vec{\text{a}}=2\hat{\text{i}}-3\hat{\text{j}}+2\hat{\text{k}}$ and $\vec{\text{b}}=2\hat{\text{i}}+3\hat{\text{j}}+\hat{\text{k}},$ respectively, then the area of the triangle OAB is:
Calculate: $\int(\text{x}^3-\frac{1}{\text{x}}+{3\text{x}})\text{dx:}$
The differential equation $\frac{d^3y}{dx^3}-5y \frac{dy}{dx}+xy=0$ represents :-
The value of $\int\frac{1}{\text{x}+\text{x}\log\text{x}}\text{ dx}$ is:
$P$  is the point of intersection of the diagonals of the parallelogram  $ABCD.$  If  $O $ is any point, then $\overrightarrow {OA} + \overrightarrow {OB} + \overrightarrow {OC} + \overrightarrow {OD} = $
Let $f(x)=3 \sin ^{4} x+10 \sin ^{3} x+6 \sin ^{2} x-3, x \in\left[-\frac{\pi}{6}, \frac{\pi}{2}\right] .$ Then, $f$ is $.....$
If  $'R'$ is the least value of $'a'$ such that the function $\mathrm{f}(\mathrm{x})=\mathrm{x}^{2}+\mathrm{ax}+1$ is increasing on $[1,2]$ and $'\mathrm{S}^{\prime}$ is the greatest value of $'a'$ such that the function $f(x)=x^{2}+a x+1$ is decreasing on $[1,2]$, then the value of $|\mathrm{R}-\mathrm{S}|$ is ..... .
Let $\alpha $ and $\beta $ be the roots of the equation $x^2 + x + 1 = 0.$ Then for $y \ne 0$ in $R,$ $\left| {\begin{array}{*{20}{c}}
{y\, + \,1}&\alpha &\beta \\
\alpha &{y\, + \,\beta }&1\\
\beta &1&{y\, + \,\alpha }
\end{array}} \right|$ is equal to
The area bounded by the curve $y = ln\, (x)$ and the lines $y = 0, y = ln\, (3)$ and $x = 0$ is equal to