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STD 12 - 7.1 inderfinite integral — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 7.1 inderfinite integral1 Mark
MCQ
$\int_{}^{} {\frac{1}{{\sqrt x }}} \sin \sqrt x \;dx = $
  • A
    $ - \frac{1}{2}\cos \sqrt x + c$
  • ✓
    $ - 2\cos \sqrt x + c$
  • C
    $\frac{1}{2}\cos \sqrt x + c$
  • D
    $2\cos \sqrt x + c$
✓

Answer

Correct option: B.
$ - 2\cos \sqrt x + c$
b
(b) Put $\sqrt x = t \Rightarrow \frac{1}{{\sqrt x }}\,dx = 2dt,$ then it reduces to
$2\int_{}^{} {\sin t\,dt} = - 2\cos t + c = - 2\cos \sqrt x + c.$

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