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STD 12 - 7.1 inderfinite integral — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 7.1 inderfinite integral1 Mark
MCQ
$\int_{}^{} {\frac{{dx}}{{4{x^2} + 9}} = } $
  • A
    $\frac{1}{2}{\tan ^{ - 1}}\left( {\frac{{2x}}{3}} \right) + c$
  • B
    $\frac{3}{2}{\tan ^{ - 1}}\left( {\frac{{2x}}{3}} \right) + c$
  • ✓
    $\frac{1}{6}{\tan ^{ - 1}}\left( {\frac{{2x}}{3}} \right) + c$
  • D
    $\frac{1}{6}{\tan ^{ - 1}}\left( {\frac{{3x}}{2}} \right) + c$
✓

Answer

Correct option: C.
$\frac{1}{6}{\tan ^{ - 1}}\left( {\frac{{2x}}{3}} \right) + c$
c
(c)$\int_{}^{} {\frac{{dx}}{{4{x^2} + 9}} = \frac{1}{4}\int_{}^{} {\frac{{dx}}{{{x^2} + {{(32)}^2}}}} } $
$ = \frac{1}{4}.\frac{2}{3}.{\tan ^{ - 1}}\left( {\frac{{2x}}{3}} \right) + c = \frac{1}{6}{\tan ^{ - 1}}\left( {\frac{{2x}}{3}} \right) + c.$

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