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STD 12 - 7.1 inderfinite integral — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 7.1 inderfinite integral1 Mark
MCQ
$\int_{}^{} {\frac{{dx}}{{(x - {x^2})}} = } $
  • ✓
    $\log x - \log (1 - x) + c$
  • B
    $\log (1 - {x^2}) + c$
  • C
    $ - \log x + \log (1 - x) + c$
  • D
    $\log (x - {x^2}) + c$
✓

Answer

Correct option: A.
$\log x - \log (1 - x) + c$
a
(a)$\int_{}^{} {\frac{{dx}}{{(x - {x^2})}} = \int_{}^{} {\left( {\frac{1}{x} + \frac{1}{{1 - x}}} \right)} {\rm{ }}dx = \log x - \log (1 - x) + c} $.

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