MCQ
$\int_{}^{} {\frac{{{e^x}}}{{{e^x} + 1}}} \,dx$ =
- A${e^x} + c$
- B$({e^x} + 1) + c$
- ✓$\log ({e^x} + 1) + c$
- Dએકપણ નહિ.
$\therefore $ $\int_{}^{} {\frac{{{e^x}}}{{{e^x} + 1}}dx = \int_{}^{} {\frac{{dt}}{t} = \log t + c = \log ({e^x} + 1) + c} } $.
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