^ -1 x 1+x^2 d x= - Vidyadip

MCQ

$\int \frac{\tan ^{-1} x}{1+x^2} d x=$

✓
$\frac{\left(\tan ^{-1} x\right)^2}{2}+C$
B
$\log \left|\tan ^{-1} x\right|+C$
C
$x \tan ^{-1} x+C$
D
$x \sin ^{-1} x+C$

✓

Answer

Correct option: A.

$\frac{\left(\tan ^{-1} x\right)^2}{2}+C$

A

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