MCQ
$\int_{}^{} {\frac{{\tan (\log x)}}{x}\;dx = } $
  • A
    $\log \cos (\log x) + c$
  • B
    $\log \sin (\log x) + c$
  • $\log \sec (\log x) + c$
  • D
    $\log {\rm{cosec}}(\log x) + c$

Answer

Correct option: C.
$\log \sec (\log x) + c$
c
(c) Put $\log x = t \Rightarrow \frac{1}{x}dx = dt$, therefore
$\int_{}^{} {\frac{{\tan (\log x)}}{x}dx = \int_{}^{} {\tan t\;dt} } $
$ = \log \sec t + c = \log \;\sec (\log x) + c$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free