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STD 12 - 7.1 inderfinite integral — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 7.1 inderfinite integral1 Mark
MCQ
$\int_{}^{} {\frac{{x - 2}}{{x(2\log x - x)}}dx} = $
  • A
    $\log (2\log x - x) + c$
  • ✓
    $\log \left( {\frac{1}{{2\log x - x}}} \right) + c$
  • C
    $\log (x - 2\log x) + c$
  • D
    $\log \left( {\frac{1}{{x - 2\log x}}} \right) + c$
✓

Answer

Correct option: B.
$\log \left( {\frac{1}{{2\log x - x}}} \right) + c$
b
(b)$\int_{}^{} {\frac{{x - 2}}{{x(2\log x - x)}}\,dx = - \int_{}^{} {\frac{{\left( {\frac{2}{x} - 1} \right)}}{{(2\log x - x)}}\,dx} } $
Now put $(2\log x - x) = t \Rightarrow \left( {\frac{2}{x} - 1} \right)\,dx = dt,$

then it reduces to $ - \int_{}^{} {\frac{1}{t}\,dt = - \log t = - \log (2\log x - x)} $
$ = \log \left( {\frac{1}{{2\log x - x}}} \right) + c$.

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