MCQ
$\int {\frac{{(x + 3){e^x}}}{{{{(x + 4)}^2}}}\,\,dx = \,\,} $
- A$\frac{1}{{{{(x + 4)}^2}}} + c$
- B$\frac{{{e^x}}}{{{{(x + 4)}^2}}} + c$
- ✓$\frac{{{e^x}}}{{x + 4}} + c$
- D$\frac{{{e^x}}}{{x + 3}} + c$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
If $\text{AB}=\text{A}$ and $\text{BA = B}$ then $\text{B}^2 $ is equal to:
$\text{B}$
$\text{A}$
$\text{-B}$
$\text{B}^2$
$1.$ Which of the following is true for $0 < x < 1$ ?
$(A)$ $0 < $ f(x) $ < \infty$
$(B)$ $-\frac{1}{2} < f(x) < \frac{1}{2}$
$(C)$ $-\frac{1}{4} < f(x) < 1$
$(D)$ $-\infty < $ f $($ x $) < 0$
$2.$ If the function $e^{-x} f(x)$ assumes its minimum in the interval $[0,1]$ at $x=\frac{1}{4}$, which of the following is true?
$(A)$ $f^{\prime}(x)$
$(B)$ $f^{\prime}(x)>f(x), 0$
$(C)$ f $^{\prime}(x)$
$(D)$ $f^{\prime}(x)$
Give the answer question $1$ and $2.$