MCQ
$\int_{}^{} {\frac{x}{{\sqrt {4 - {x^4}} }}dx} = $
- A${\cos ^{ - 1}}\frac{{{x^2}}}{2}$
- B$\frac{1}{2}{\cos ^{ - 1}}\frac{{{x^2}}}{2}$
- C${\sin ^{ - 1}}\frac{{{x^2}}}{2}$
- ✓$\frac{1}{2}{\sin ^{ - 1}}\frac{{{x^2}}}{2}$
we get the required integral $ = \frac{1}{2}{\sin ^{ - 1}}\frac{{{x^2}}}{2}$.
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$f(x) = \left\{ {\begin{array}{*{20}{l}}
{\frac{{k\cos x}}{{\pi - 2x}},}&{{\rm{ if }}\,x\, \ne \,\frac{\pi }{2}}\\
{3,}&{{\rm{ if }}\,x\, = \,\frac{\pi }{2}}
\end{array}} \right.$ at $x = \frac{\pi }{2}$
| X = xi | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| P(X = Xi) | 0 | 2p | 2p | 3p | p2 | 2p2 | 7p2 | 2p |
$\frac{1}{10}$
$-1$
$-\frac{1}{10}$
$\frac{1}{5}$