MCQ
$\int_{}^{} {{e^{{x^2}}}x\;dx} $ is equal to
- A${e^{{x^2}}}$
- ✓$\frac{1}{2}{e^{{x^2}}}$
- C$2{e^{{x^2}}}$
- D$\frac{{{e^{{x^2}}} - {x^2}}}{2}$
(Put ${x^2} = t \Rightarrow dt = 2x\,dx)$.
$ = \frac{1}{2}\int_{}^{} {{e^t}dt} = \frac{1}{2}{e^t} = \frac{1}{2}{e^{{x^2}}}$,
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| X: | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| P(X): | 0.15 | 0.23 | 0.12 | 0.10 | 0.20 | 0.08 | 0.07 | 0.05 |
Find the events E = {X : X is a prime number}, F{X : X < 4}, the probability $\text{P}(\text{E}\cup\text{F})$ is:
$\quad \quad \quad \quad \quad 5 x+1,\quad \quad \quad \quad \quad x \leq 2$, then