MCQ
$\int {{e^x}\left( {\frac{{1 - \sin x}}{{1 - \cos x}}} \right)\,\,dx} $ is equal to
- A$ - {e^x}\tan \,\left( {x/2} \right)$
- ✓$ - {e^x}\cot \,\left( {x/2} \right)$
- C$ - \frac{1}{2}{e^x}\tan \,\left( {\frac{x}{2}} \right)$
- D$\frac{1}{2}{e^x}\cot \,\left( {\frac{x}{2}} \right)$