MCQ
$\int e^x\left(\frac{1-x}{1+x^2}\right)^2 d x$ बराबर है
- ✓$\frac{e^x}{1+x^2}+c$
- B$\frac{-e^x}{1+x^2}+c$
- C$\frac{e^x}{\left(1+x^2\right)^2}+c$
- D$\frac{-e^x}{\left(1+x^2\right)^2}+c$
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