MCQ
$\int {{{\left( {\frac{{x + 2}}{{x + 4}}} \right)}^2}{e^x}\,\,dx} $ is equal to
  • ${e^x}\left( {\frac{x}{{x + 4}}} \right) + c$
  • B
    ${e^x}\left( {\frac{{x + 2}}{{x + 4}}} \right) + c$
  • C
    ${e^x}\left( {\frac{{x - 2}}{{x + 4}}} \right) + c$
  • D
    $\left( {\frac{{2x{e^x}}}{{x + 4}}} \right) + c$

Answer

Correct option: A.
${e^x}\left( {\frac{x}{{x + 4}}} \right) + c$
a
(a) $I = \int {{{\left( {\frac{{x + 2}}{{x + 4}}} \right)}^2}{e^x}dx} $$ = \int {{e^x}\left[ {\frac{{{x^2} + 4x + 4}}{{{{(x + 4)}^2}}}} \right]} \,dx$
$ \Rightarrow I = \int {{e^x}\left[ {\frac{{x(x + 4)}}{{{{(x + 4)}^2}}} + \frac{4}{{{{(x + 4)}^2}}}} \right]\,dx} $
$ = {e^x}\left[ {\frac{x}{{x + 4}} + \frac{4}{{{{(x + 4)}^2}}}} \right]\,dx$$ = {e^x}\left( {\frac{x}{{x + 4}}} \right) + c$.

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