MCQ
$\int_{}^{} {{{(\log x)}^2}\;dx = } $
- A$x{(\log x)^2} - 2x\log x - 2x + c$
- B$x{(\log x)^2} - 2x\log x - x + c$
- ✓$x{(\log x)^2} - 2x\log x + 2x + c$
- D$x{(\log x)^2} - 2x\log x + x + c$
then it reduces to $\int_{}^{} {{t^2}.\,{e^t}dt = {t^2}{e^t} - 2t{e^t} + 2{e^t} + c} $
$ = x{(\log x)^2} - 2x\log x + 2x + c$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{|p{0.4\linewidth}|p{0.4\linewidth}|}\hline \text { Column } & \text { Maximum of } z \\\hline \text { A } & 300 \\\hline \text { B } & 325 \\\hline\end{array}$
$ x+(\sqrt{2} \sin \alpha) y+(\sqrt{2} \cos \alpha) z=0 $
$ x+(\cos \alpha) y+(\sin \alpha) z=0 $
$ x+(\sin \alpha) y-(\cos \alpha) z=0$
ને એક અસામાન્ય ઉકેલ હોય, તો $\alpha \in\left(0, \frac{\pi}{2}\right)$ બરાબર ............ છે.