Maharashtra BoardEnglish MediumSTD 12 ScienceMathsDefinite Integration2 Marks
MCQ
$\int_{-\pi / 2}^{\pi / 2} \frac{\sin x}{1+\cos ^2 x} e^{-\cos ^2 x} d x$ is equal to
A
$2 e^{-1}$
B
1
✓
$0$
D
-1
✓
Answer
Correct option: C.
$0$
(C) Let $f (x)=\frac{\sin x}{1+\cos ^2 x} e ^{-\cos ^2 x}$ $\begin{array}{ll}\therefore & f (-x)=-\frac{\sin x}{1+\cos ^2 x} e ^{-\cos ^2 x}=- f (x) \\ \therefore & f (x) \text { is an odd function. } \\ \therefore & \int_{-\pi / 2}^{\pi / 2} f (x) d x=0\end{array}$
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