MCQ
$\tan ^{-1}(\sqrt{3})-\cot ^{-1}(-\sqrt{3})$ is equal to
  • A
    $\pi$
  • $-\frac{\pi}{2}$
  • C
    $0$
  • D
    $\frac{\pi}{4}$

Answer

Correct option: B.
$-\frac{\pi}{2}$
(B) $\tan ^{-1}(\sqrt{3})-\cot ^{-1}(-\sqrt{3})$
$\begin{array}{l}=\tan ^{-1} \sqrt{3}-\left[\pi-\cot ^{-1} \sqrt{3}\right] \\ -\tan ^{-1} \sqrt{3}+\cot ^{-1} \sqrt{3} \quad \pi \\ =\frac{\pi}{2}-\pi \\ =-\frac{\pi}{2}\end{array}$

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