Question
$\int_{}^{} {{{\sin }^2}x\cos x\;dx} $ =
$\sin x = t $ रखने पर $ \Rightarrow \cos x\,dx = dt$
$\therefore \,\,\,I = \int_{}^{} {{t^2}dt} = \frac{{{t^3}}}{3} + c = \frac{{{{\sin }^3}x}}{3} + c$.
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