MCQ
$\int_0^{\frac{\alpha}{3}} \frac{f(x)}{f(x)+f\left(\frac{\alpha-3 x}{3}\right)} d x=$
  • A
    $\frac{2 \alpha}{3}$
  • B
    $\frac{\alpha}{2}$
  • C
    $\frac{\alpha}{3}$
  • $\frac{\alpha}{6}$

Answer

Correct option: D.
$\frac{\alpha}{6}$
(D)
Let $I=\int_0^{\frac{\alpha}{3}} \frac{f(x)}{f(x)+f\left(\frac{\alpha-3 x}{3}\right)} d x$
$\Rightarrow I =\int_0^{\frac{\alpha}{3}} \frac{ f (x)}{ f (x)+ f \left(\frac{\alpha}{3}-x\right)} d x$
$\int_0^{ a } \frac{ f (x)}{ f (x)+ f ( a -x)} d x=\frac{ a }{2}$
$=\frac{\frac{\alpha}{3}}{2} $
$=\frac{\alpha}{6}$

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