_0^ 2 1 1+ x d x= - Vidyadip

MCQ

$\int_0^{\frac{\pi}{2}} \frac{1}{1+\cot x} d x=$

A
$\frac{\pi}{2}$
B
$0$
✓
$\frac{\pi}{4}$
D
$\frac{\pi}{3}$

✓

Answer

Correct option: C.

$\frac{\pi}{4}$

C

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from समाकलन→समाकलन — all question types→गणित कक्षा 12 साइन्स question papers→CBSE Board कक्षा 12 साइन्स question papers→CBSE Board question paper generator→

Similar questions

$\left|\begin{array}{ll}10 & 2 \\ 35 & 7\end{array}\right|=$................

$\int_a^b e^x d x=$

$\frac{d}{d x}\left(\cos ^2 \frac{x}{2}\right)=$

$\left[\begin{array}{cc}13 & 15 \\ -1 & 4\end{array}\right]\left[\begin{array}{ll}2 & 0 \\ 0 & 2\end{array}\right]=$

यदि $A=\tan ^{-1}$ तब sin 2A का मान निम्न है:

सदिश $19 \vec{i}+5 \vec{j}-6 \vec{k}$ का मापांक है

$\int \cot ^2 x d x=$

$\tan ^{-1}\left(\frac{x}{y}\right)-\tan ^{-1}\left(\frac{x-y}{x+y}\right)=$

$\frac{d}{d x}\left(e^{x-a}\right)=$

अगर $\left[\begin{array}{cc}x+y & 3 \\ 4 & x-y\end{array}\right]=\left[\begin{array}{cc}1 & 3 \\ 4 & -3\end{array}\right]$ तब $(x, y)$ है :