Question
$\int_{\,0}^{\,2} {\,|x - 1|\,dx = } $
$={ \int_0^1 {( - x + 1)dx + \int_1^2 {(x - 1)\,dx} } } $
$ = \left( {\frac{{ - {x^2}}}{2} + x} \right)_0^1 + \left( {\frac{{{x^2}}}{2} - x} \right)_1^2 = 1.$
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$a_{i j}=\frac{1}{2}|-3 i+j|$