MCQ
$\int_0^{2\pi } {{e^{x/2}}.\sin \left( {\frac{x}{2} + \frac{\pi }{4}} \right)\,dx = } $
- A$1$
- B$2\sqrt 2 $
- ✓$0$
- DNone of these
==> $I = 2\int_0^\pi {{e^t}\sin \left( {t + \frac{\pi }{4}} \right)dt} $
$= 2\left[ {\frac{{{e^t}}}{{\sqrt {1 + 1} }}\sin \left( {t + \frac{\pi }{4} - {{\tan }^{ - 1}}\frac{1}{1}} \right)} \right]_0^\pi $
$ = \frac{2}{{\sqrt 2 }}\left[ {{e^t}\sin t} \right]_0^\pi = \frac{2}{{\sqrt 2 }}[0] = 0$.
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