Question
$\int_0^{b - c} {\,\,f''(x + a)\,dx = } $
$ = [f'(x + a)]_0^{b - c} = f'(b - c + a) - f'(a)$.
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$\left(\sin ^2 2 x\right) \frac{d y}{d x}+\left(8 \sin ^2 2 x+2 \sin 4 x\right) y$
$=2 e ^{-4 x}(2 \sin 2 x+\cos 2 x), \quad x \in\left(0, \frac{\pi}{2}\right)$
$y \left(\frac{\pi}{4}\right)= e ^{-\pi}$ का हल वक्र $y = y ( x )$ है, तो $y \left(\frac{\pi}{6}\right)$ बराबर है :