Question
$\int_0^{\pi /2} {\,\,\log \tan x\,dx = } $
$ = \int_0^{\pi /2} {\log \sin x\,dx - \int_0^{\pi /2} {\log \cos x\,dx = 0} } $,
$\left\{ \because \int_{0}^{a}{f(x)dx=\int_{0}^{a}{f(a-x)dx}} \right\}$.
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