MCQ
$\int_{\,0}^{\,\pi /2} {\{ x - [\sin x]\} \,dx} =$
- ✓$\frac{{{\pi ^2}}}{8}$
- B$\frac{{{\pi ^2}}}{8} - 1$
- C$\frac{{{\pi ^2}}}{8} - 2$
- Dએકપણ નહીં.
$ = \left( {\frac{{{x^2}}}{2}} \right)_0^{\pi /2}$
$ = \frac{{{\pi ^2}}}{8}$, $ [ \because \int_{\,0}^{\,\pi /2} {[\sin x]\,dx = 0} ]$.
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