MCQ
$\int_{\,0}^{\,\pi } {{{\cos }^3}x\,dx = } $
- A$ - 1$
- ✓$0$
- C$1$
- D$\pi $
$\{\because \,\,{{\cos }^{3}}(\pi -x)=-{{\cos }^{3}}x\}$ .
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$[A]$ $x=-1$ $[B]$ $x=0$ $[C]$ $x=2$ $[D] x=1$